Question

x^2+6x+7=0

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Answer 1

Answer:

We can't facotr this

for

ax^2+bx+c=0

x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}

1x^2+6x+7

x= \frac{-6+/- \sqrt{6^2-4(1)(7)} }{2(1)}

x= \frac{-6+/- \sqrt{36-28} }{2}

x= \frac{-6+/- \sqrt{8} }{2}

x= \frac{-6+/- 4\sqrt{2} }{2}

x= -3+/- 2\sqrt{2}

x= -3+ 2\sqrt{2} and x=-3- 2\sqrt{2}

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Answer 2

Answer:

${\red{\underline {\underline {\bold{Given:-}}}}}$

${x}^{2}+6x+7 =0$

${\blue{\underline{\underline{\bold{To\:Find}}}}}$

The roots of the given equation (value of x)

${\green{\underline{\underline{\bold{Solution:-}}}}}$

the solution is in the attachment mate.

${\pink{\underline{\underline{\bold{Additional\: Information:-}}}}}$

We can also find the roots by following methods:-

Completing square method

Factorisation method

By using quadratic formula

Step-by-step explanation: