Question

x^2+6x,+7 =0

solve frm quadratic formula​

Answer 1

The first term is, x2 its coefficient is 1 .

The middle term is, -6x its coefficient is -6 .

The last term, "the constant", is -7

Step-1 : Multiply the coefficient of the first term by the constant 1 • -7 = -7

Step-2 : Find two factors of -7 whose sum equals the coefficient of the middle term, which is -6 .

-7 + 1 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and 1

x2 - 7x + 1x - 7

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-7)

Add up the last 2 terms, pulling out common factors :

1 • (x-7)

Step-5 : Add up the four terms of step 4 :

(x+1) • (x-7)

Which is the desired factorization

Equation at the end of step 1 :

(x + 1) • (x - 7) = 0

Answer 2

Answer:

$\huge\star\underline\texttt{Answer :)}$

x^2+6x-7=0

=>x^2+2*3x+3^2-9-7=0

=>(x+3)^2-16=0

=>(x+3)^2-(4)^2=0

=>(x+3+4)(x+3-4)=0

=>(x+7)(x-1)=0

=>x=1,-7

Formula used

(x+y)^2=x^2+2xy+y^2 and x^2-y^2=(x+y)(x-y).

Here is how you can solve this question:

First, bring the constant term -7 to the other side.

Then add 1/2(coefficient of x)^2 to both the sides.

Simplify and get the answer