Question

X^2+6x-8=0


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Answer 1

Step-by-step explanation:

x² + 6x - 8 = 0 ( solving it using middle factorization )

=> x² + ( 4+2 )x - 8 =0

=> x² + 4x + 2x - 8 =0

=> x( x+4) -2( x+4) =0

=> (x+4) ( x-2) =0

therefore,

x + 4=0 , x - 2=0

=> x= -4 => x= 2

Answer 2

Answer:

$\huge\boxed{\fcolorbox{red}{pink}{Your's Answer}}$

$\red {QUESTION}$

Solve:-

${x}^{2} + 6x - 8 = 0$

But, the correct question is${x}^{2} - 6x + 8</strong><strong> </strong><strong>=</strong><strong> </strong><strong> </strong><strong>0</strong><strong> </strong><strong>$

$\green {ANSWER}$

The zeroes are 2 and 4.

Explanation:-

${x}^{2} - 6x + 8 = 0$

(by splitting the middle term)

${x}^{2} - 4x - 2x + 8 = 0$

$=> x(x - 4) - 2(x - 4) = 0$

$=> (x - 2)(x - 4) = 0$

$x - 2 = 0 \: or \: x - 4 = 0$

$x = 2</em><em> </em><em>,</em><em> </em><em>4$

$<marquee behaviour-move><font color="orange"><h1>It'z ANKUSH here</h1></marquee>$

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