Math, asked by sakshamdev54, 9 months ago

X^2+6X-(a^2+2a-8)=0
Find X???​

Answers

Answered by kumarrram98
1

x²+6x-(a²+2a-8)=0

firstly solve the (a²+2a-8)

a²+2a-8

a²+4a-2a-8

a(a+4)-2(a+4)

(a-2)(a+4)

a=2and a=-4

then solve given equation

x²+6x-2. / x²+6x-(-4)=x²+6x+4

a=1. / a=1

b=6. / b=6

c=-2. / c=4

D=b²-4ac. / D=b²-4ac

D=(6)²-[4×1×(-2)]. / D=(6)²-4(4)

D=36-(-8). / D=36-16

D=36+8. / D=20

D=44.

x=-b+D. ,,. -b-√D

2a. 2a

put all

x=-6+211 , -6-211 / x=-6+25 ,. -6-25

2. 2. /. 2. 2

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