x^2-6x +[x]+7 Please solve
mahima1384:
greatest integer
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x^2 -6x + 7 = - [x]
( x-3)^2 -2 = -[x]
(x-3)^2 = 2 - [x]
x = √ 2- [x] +. 3
here x is positive
[x] = 0,1,2....
we have to check possibility
only [x] =0 satisfying
because [x] = 1,2 would give x to be integer
so x value should be √2 + 3
( x-3)^2 -2 = -[x]
(x-3)^2 = 2 - [x]
x = √ 2- [x] +. 3
here x is positive
[x] = 0,1,2....
we have to check possibility
only [x] =0 satisfying
because [x] = 1,2 would give x to be integer
so x value should be √2 + 3
why positive and negative
now what to do please tell
sorry for that
No greatest integer I means to say I should write this in question that's why
Ok Thanks
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