Question

x^2+7x-1=0 find the value of discriminant​

Answer 1

Given :

$\sf {x}^{2} + 7x - 1 = 0$

To find :

$\sf \: value \: of \: discriminant$

Formula used :

$\sf d = { {b}^{2} - 4ac}$

Where :-

• d = discriminant
• a = coefficient of x²
• b = coefficient of x
• c = constant

Solution :

It is given :-

$\bf {x}^{2} + 7x - 1 = 0$

Here :-

• a = 1
• b = 7
• c = -1

Now :-

$\implies\sf d = { {b}^{2} - 4ac}$

$\implies\sf d = { {7}^{2} -( 4 \times 1 \times - 1)}$

$\implies\sf d = { 49 -( - 4 )}$

$\implies\sf d = 49 + 4$

$\implies\sf d =53$

Answer :

$\sf \: The \: value \: of \: discriminant = 53$

Answer 2

Question :-

✎ Which of the following is the value of the discriminant for x² + 7x + 1 = 0 :-

A) -5

B) 17

C) 45

Given :-

x² + 7x + 1 = 0

Find Out :-

What is the discriminate value of that equation.

Solution :-

✭ x² + 7x + 1 = 0

here,

⊙ a = 1

⊙ b = 7

⊙ c = 1

As we know that :

✯ $\red{ \boxed{\sf{Discriminate\: (D) =\: b^2 - 4ac}}}$ ✯

By putting values we get,

➙ Discriminate = (7)² - 4(1)(1)

➙ Discriminate = 49 - 4 × 1 × 1

➙ Discriminate = 49 - 4

➙ ${\small{\bold{\purple{\underline{Discriminate = 45}}}}}$

Henceforth, the discriminate value of that equation is 45.

Correct options is C) 45.✅