Question

x^2+7x-18=0
please answer this question​

Answer 1

Solution:- x^2+7x-18=0

Solving x^2+7x-18 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 ,

- B ± √ B^2-4AC

x = ————————

2A

In our case, A = 1

B = 7

C = -18

Accordingly, B^2 - 4AC =

49 - (-72) =

121

Applying the quadratic formula :

-7 ± √ 121

x = ——————

2

Two real solutions:

x =(-7+√121)/2=(-7+11)/2= 2.000

or:

x =(-7-√121)/2=(-7-11)/2= -9.000

hence

x = 2

x = -9

I hope it helps you .