Question

x^2+7x=9


pls solve it's argent​

Answer 1

Answer:

x² + 7x - 9 = 0

x = - b ± √b²- 4ac / 2a

x = -7 ± √7²- 4(1)-9 / 2(1)

x = - 7 ± √49 + 36 / 2

x = -7 ± √85 / 2

x = -7 + √85/2

and

x = -7 - √85 / 2

Thank you

Answer 2

$\huge\underline\bold\red{Answer}$

Subtract 9 from both sides

x²+7x-9=9-9

x²+7x-9=0

For this equation: a=1, b=7, c=-9

1x²+7x-9=0

Use quadratic formula with a=1, b=7, c=-9.

$x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{ - (7) + \sqrt{ {7}^{2} - 4(1)( - 9) } }{2(1)}$

$x = \frac{ - 7 + \sqrt{85}}{2}$

$x = \frac{ - 7}{2} + \frac{ 1}{ 2} \sqrt{85} ,x = \frac{ - 7}{2} + \frac{ - 1}{ 2} \sqrt{85}$

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Hope it helps :)