Question

x ^ 2 + 8x + 2 = 0 Find the value of (1 / alpha + 1 / beta) with quadratic equation having two basic alpha and beta.​
plzz.. fast its urgent.

Answer 1

Answer:

-4

Step-by-step explanation:

sum of roots=a+b=-b/a=-8

product of roots=ab=c/a=2   1/a+1/b=a+b/ab=-8/2=-4

a=alpha  b=beta

Answer 2

ANSWER....

$let \: \alpha \: and \: \beta \: be \: the \: two \: roots \: of \\ \: the \: equation \: {x}^{2} + 8x + 2 \\ \\ where \: a = 1 \\ b = 8 \\ c = 2 \\ \\ \alpha \: + \: \beta = \frac{ - b}{a} \\ \\ \alpha + \beta = \frac{ - 8}{1} .......eq(1) \\ \\ ( \alpha ) \times ( \beta ) = \frac{c}{a} \\ \\ \alpha \times \beta = \frac{2}{1} ......eq(2) \\ \\ acc \: to \: your \: question \\ \frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ \alpha + \beta }{ \alpha \times \beta } \\ \\ put \: the \: value \: eq(1) \: eq(2) \: here \\ \\ \frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ - 8}{2} \\ \\ \frac{1}{ \alpha } + \frac{1}{ \beta } = - 4$

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