X^2 - 8x + 4 =0 by completing the square
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hope this will help you
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To solve : x^2-8x+4=0
Solution:
a=1 ,b=-8 , c=4
D=b^2 -4ac
=64-16
=48
x= - b +√D/2a, x= -b-√D/2a
x=8+4√3/2,x=8-4√3/2
x=12√3/2,x=4√3/2
x=6√3, x=2√3
Therefore two roots of quadratic polynomial are 6√3, 2√3 .
Hope this will help you:)
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