Question

x^2+8x+7 factorise this by finding the product of the last digit

Answer 1

Answer:

x+7 and x+1 are the factors.

Step-by-step explanation:

x² + 8 x + 7

Here the coefficient of x² term is 1. So it is simpler to find the factors.

Factors of the constant term 7 are  = 7 and 1.  

Their sum = 8, which is equal to the coefficient of x in the middle term.

So the factors will be x+7 and x+1 .  

Since there are only two factors for 7 , this question is easy to solve.

So   x² + 8 x + 7 = (x+7)*(x+1)

Answer 2

Answer:-

x+7 and x+1 are the factors.

Step-by-step explanation:

x² + 8 x + 7

Here the coefficient of x² term is 1. So it is simpler to find the factors.

Factors of the constant term 7 are  = 7 and 1.  

Their sum = 8, which is equal to the coefficient of x in the middle term.

So the factors will be x+7 and x+1 .  

Since there are only two factors for 7 , this question is easy to solve.

So   x² + 8 x + 7 = (x+7)*(x+1)