Question

x^2-8x-8y+16+y^2
solve this math ​

Answer 1

Answer:

Let's consider this as an equation (which may lead to a conic section).

x2-8x-8y+16+y2 = 0

x2 -8x + 16 + y2 - 8y = -16.

Now, applying the rule for completing the square in the x "department" we add the square of half of (-8) to each side, i.e. 16.

And by completing the square in the y "department we add the square of half of the coefficient of y, also, to each side, i.e. another +16.

Result: (x-4)2 + (y-4)2 = 16; this is a circle with center at (4,4) and radius 4 (the square root of the right hand side).

Check the work!

Answer 2

${x}^{2} - 8x - 8y + 16 + {y}^{2}$

This can't be solved further.