Question

x^2=8x+y and y^2=x+8y,find value of x+y please no spams

Answer 1

Answer:

$\large{\bold{x+y=(\frac{x}{3})^2+(\frac{y}{3})^2}}$

Step-by-step explanation:

$Given\\\\x^2=8x+y<1>\\\\y^2=x+8y<2>\\\\<1>+<2>\\\\=>x^2+y^2=9(x+y)\\\\=>x^2+y^2=3^2(x+y)\\\\=>\frac{x^2+y^2}{3^2}=x+y\\\\=>x+y=(\frac{x}{3})^2+(\frac{y}{3})^2$

HOPE IT HELPS

Answer 2

Hola mate

Here is your answer -

x²+y² = 8x+y+x+8y

x²+y² = 9x+9y

x²+y² = 9(x+y)