Question

(x^2-9)divide by x+3=4 divide by7

Answer 1

$\frac{ x^{2} -9}{x+3} = \frac{4}{7} \\\\ \frac{ x^{2} - 3^{2} }{x+3} = \frac{4}{7}\\\\ \frac{(x-3)(x+3)}{(x+3)} = \frac{4}{7} \\\\ (x-3) = \frac{4}{7} \\\\ x = \frac{4}{7} + 3 \\\\ x = \frac{(4+21)}{7} \\\\ x = \frac{25}{7}$