Question

X^2 - 9
————
X + 3

Please help factorise this equation

Answer 1

$\huge\bold\red{Question}$

• X^2 - 9
• ————
• X + 3
• factorise this equation

$\huge\bold\red{Solution}$

• $= > \frac{ {x}^{2} - 9}{x + 3} \\ \\ \\ = > \frac{x - 3 \times x \div 3}{x \div 3}reduce \: x + 3 \: with \: x - 3 \\ \\ then \: as \: \: x \div 3 \: is \: in \: both \: \: numerator \: and \\ denominator \: so \: will \: cancle \: them.\\ \\ \\ = >x - 3 \: \: (answer)$

Answer 2

x-3 is the answer of the question