Question

X^2-9x+1=0 solve by quadratic formula

Answer 1

Step-by-step explanation:

${x}^{2} - 9x + 1 = 0 \\ here \\ a = 1\: \: \: b = - 9 \: \: \: \: \: c = 1 \\ so \\ d = {b}^{2} - 4ac \\ = { - 9}^{2} - 4 \times 1 \times 1 \\ = 81 - 4 \\ = 77 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ = \frac{ - ( - 9) - \sqrt{77} }{2 \times 1} \\ = \frac{9 - \sqrt{77} }{2} \\ or \frac{9 + \sqrt{77} }{2}$

i hope it will be helpful

Answer 2

Answer:

Step-by-step explanation:

Here,a=1,b=-9 and c=1

Using the formula,

x=-b+/-√b^2-4ac/2a

=>x=-(-9)+/-√(-9)^2-4×1×1/2×1

=>x=9+/-√81-4/2

=>x=9+√77/2 or 9-√77/2