x^2 + 9y^2 - 6xy. find x and y?
Answers
Answered by
2
Heya!!Here is your answer friend ⤵⤵
↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔
![x {}^{2} + 9y {}^{2} - 6xy \\ using \: identity \: (x - y) {}^{2} = x {}^{2} + y {}^{2} - 2xy \\ \\ (x) {}^{2} + (3y) {}^{2} - 2 \times x \times 3 \\ = > (x - 3y) {}^{2} \\ x = x \\ y = 3y \\ \\ x {}^{2} + 9y {}^{2} - 6xy \\ using \: identity \: (x - y) {}^{2} = x {}^{2} + y {}^{2} - 2xy \\ \\ (x) {}^{2} + (3y) {}^{2} - 2 \times x \times 3 \\ = > (x - 3y) {}^{2} \\ x = x \\ y = 3y \\ \\](https://tex.z-dn.net/?f=x+%7B%7D%5E%7B2%7D++%2B+9y+%7B%7D%5E%7B2%7D++-+6xy+%5C%5C+using+%5C%3A+identity+%5C%3A+%28x+-+y%29+%7B%7D%5E%7B2%7D++%3D+x+%7B%7D%5E%7B2%7D++%2B+y+%7B%7D%5E%7B2%7D+-++2xy+%5C%5C++%5C%5C+%28x%29+%7B%7D%5E%7B2%7D++%2B+%283y%29+%7B%7D%5E%7B2%7D++-+2+%5Ctimes+x++%5Ctimes+3+%5C%5C+%3D++%26gt%3B++%28x+-+3y%29+%7B%7D%5E%7B2%7D++%5C%5C+x+%3D+x+%5C%5C+y+%3D+3y+%5C%5C++%5C%5C+)
Hope it helps you ✌✌☺
↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔
Hope it helps you ✌✌☺
Answered by
3
Hope you understand what I say
Attachments:
![](https://hi-static.z-dn.net/files/d79/3ce7b58351f04957925fcb5a8e3784ab.png)
Similar questions