Question

x^2 + (a+1)x +b , alpha = 2, ß = -3 find a & b​

Answer 1

ans----------

1. x^2+(a+1)x+b
2. alpha+beta= -(a+1)/1
3. put the value of alpha and beta
4. -a-1=2-3
5. a= -1+2-3=-2
6. therefore a =-2
7. alpha×beta=b/1=b
8. put the value of alpha and beta
9. b=2×(-3)=-6
10. ans----------> a=-2,b=-6

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