x^2-a^2+4ab-4b^2
Factorise it
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Required Answer
= x² - a² + 4ab - 4b² ∵(a - b)²=a²+2ab-b²
= (x)² - (a - 2b)²
= (x - a - 2b)(x + a - 2b) Ans
Answered by
4
Required Answer:-
Given To Factorise:
- x² - a² + 4ab - 4b²
Solution:
We have,
= x² - a² + 4ab - 4b²
= x² - (a² - 4ab + 4b²)
= x² - [(a)² - 2 × (a) × (2b) + (2b)²]
= x² - (a - 2b)² [∵ (a - b)² = a² - 2ab + b²]
= [x + (a - 2b)][x - (a - 2b)]
= (x + a - 2b)(x - a + 2b)
→ Hence, the factorised form is (x + a - 2b)(x - a + 2b)
Answer:
- (x + a - 2b)(x - a + 2b)
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