Question

x^2+[(a/a+b)+(a+b/a)]x+1=0

Answer 1

Answer:

heya mate gm(●__●)

#anu⊙.☉

Step-by-step explanation:

Heya User, Let --> y = ( a / ( a + b ) ) ; --> x² + [ y + 1/y ]x + 1 = 0 => yx² + [ y² + 1 ] x + y = 0 => yx² + y²x + x + y = 0

Answer 2

HEY BRO SO THIS PROBLEM WILL BE SOLVED LIKE THIS.....

x² + [A/ A+B + A+B/A] x + 1 = 0

NOW BY OPENING THE BRACKET

=> x² + Ax/ A+B + (A+ B)x/ A + 1 = 0

SO NOW WE WILL SPLIT 1 INTO (A/ A+B) ( A+ B/A) .........COZ THATS ALSO 1.

=> x² + Ax/ A+B + (A+ B)x/A + (A/A+B) (A+B/A)=0

NOW TAKING (A+ B / A) and x COMMON SO,

=> x( x + A/A+B) + (A+B/A) (x + A/A+B) = 0

NOW BY TAKING ( x + A/A+B) common then

=> (x + A+B/A)(x + A/A+B) = 0

=> x+ A+B/A = 0 and x + A/A+B = 0

So, x = - A+B/A and x= - A/A+B

HOPE THIS WILL HELP U.

PLZ MARK AS BRAINLIEST........