((x ^ 2) ^ (a + b) * (x ^ 2) ^ (b + c) * (x ^ 2) ^ (c + a))/((x ^ a * x ^ b * x ^ c) ^ 4)
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Answer:
1 is the answer
Step-by-step explanation:
IF BASE IS SAME AND USE MULTIPLY IN BETWEEN TWO BASE THEN POWER IS ADD
((x ^ 2) ^ (a + b) * (x ^ 2) ^ (b + c) * (x ^ 2) ^ (c + a))/((x ^ a * x ^ b * x ^ c) ^ 4)
((x ^ 2) ^ (a + b) * (x ^ 2) ^ (b + c) * (x ^ 2) ^ (c + a))
= (( x^2) ^ ( a+b) +(b+c) +(c+a)) / (x ^ a * x ^ b * x ^ c) ^ 4)
then subtract it value of division
= x^2 ^ ( a + b + b +c + c + a)
= x^2 ^ 2(a + b + c)) / (x ^ a * x ^ b * x ^ c) ^ 4)
= x^4 ( a + b + c) / ( x ^a + b + c) ^4
= 1
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