x^2-(a+b)x+ab
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Answer:
given
x² -(a +b)x + ab
= x² -ax -bx + ab
= x(x -a) -b( x -a)
= (x -a)(x -b)
so, the factors are (x-a) and ( x -b)
to find the zeros
(x -a)(x -b) = 0
=> x -a = 0. or , x -b = 0
=> x = a or, x = b
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