Question

(x-2) and (2x-1) are factors of ax^2+5x+b show that a-b=0

Answer 1

Solution :-

given equetion:-

$a {x}^{2} + 5x + b \\ factor \: of \: this \: equetion \\ (x - 2)ans(2x - 1) \\ now \: we \: have \\ (x - 2)(2x - 1) \\ 2 {x}^{2} - 4x - x + 2 \\ 2 {x}^{2} - 5x + 2 \\ compare \: by \: a {x}^{2} + 5x + b \\ now \: \\ a = 2 \\ b = 2 \\ (a - b) = 0 \\ proved \: that$