Question

x/2 and [(3xy²)/4+x²y]​

Answer 1

Answer:

( x³ + 4 xy² ) / ( 4 x²y + y³ ) = 15/16⇒ 16 ( x³ + 4 xy² ) = 15 ( 4 x²y ... ( 2 x - 3 y )³ + 2 ( 4 x³ - 12 x²y + 5 xy² + 6 y³ ) = 0.