Question

x/2 and [(3xy²)/4+x²y]​​

Answer 1

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Answer 2

(x³ + 4 xy² ) / (4x²y + y³ ) = 15/16 ⇒ 16 (x³ + 4 xy²) 15 (4x²y... (2x-3y)³+2 (4 x³ - 12 = x²y + 5 xy² + 6y³ ) = 0.

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