Question

x-2 and x-2 are factors of px2+5x+r,show that p=r
can anyone answer this question ​

Answer 1

Let f(x) = px2 + 5 x + rIf (x - 2) is a factor of f (x), then by factor theoremf(2) = 0 | x - 2 = 0 ⇒ x = 2⇒ p(2)2 + 5(2) + r = 0⇒ 4p + r + 10 = 0 .