(x-2) and (x-3) are factors of x^2+ax+p find the value of p
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Answer:
a = -5 and p = 6
Step-by-step explanation:
Since, it is given that 2,3 are the roots of the equation,
sum of the roots = 2 + 3 = 5
product of the roots = 6
The quadratic equation is x² - (sum) x + product = 0
So, x² - 5x + 6 is the equation.
Comparing with x²+ax+p, we get a = -5 and p = 6
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