Question

x=-2 and x2 + y2 + 3xy = -5 ,
y=?​

Answer 1

Answer:

$x = - 2 \\ {x }^{2} + {y}^{2} + 3xy = - 5 \\ { (- 2)}^{2} + {y}^{2} + 3( - 2)(y) = - 5 \\ 4 + {y}^{2} - 6y = - 5 \\ {y}^{2} - 6y + 9 = 0 \\ {y}^{2} -3 y - 3y + 9 = 0 \\ y(y - 3) - 3(y - 3) = 0 \\ (y - 3)(y - 3) = 0 \\ {(y - 3)}^{2} = 0 \\ y - 3 = 0 \\ y = 3$

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Answer 2

Answer:

1/4

Step-by-step explanation:

2*-2+2y+3*-2y=-5

-4+2y-6y=-5

-4-4y=-5

-4y=-5+4

-4y=-1

y=1/4