Question

x^2-ax-b^2=0 comment upon the naturev of roots of the following equation​

Answer 1

Given quadratic equation,

x

2

−ax−b

2

=0

Here, a=1,b=−a and c=−b

2

So, the Discriminant (D)=b

2

−4ac

D=(a)

2

−4(1)(−b

2

)

=a

2

+4b

2

a

2

+4b

2

is always positive value.

Thus D>0, and the roots of the equation is real and unequal

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