Question

x^2 – ax – b2 = 0. find the nature of the roots​

Answer 1

Step-by-step explanation:

Given quadratic equation,

x2−ax−b 2=0

Here, a=1,b=−a and c=−b2

So, the Discriminant (D)=b

2−4ac

D=(a)

2−4(1)(−b 2 )

=a 2+4b2

a

2

+4b

2

is always positive value.

Thus D>0, and the roots of the equation is real and unequal