x-2 divided by 3x^2-5x-22
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Factoring 3x2-5x-22
The first term is, 3x2 its coefficient is 3 .
The middle term is, -5x its coefficient is -5 .
The last term, "the constant", is -22
Step-1 : Multiply the coefficient of the first term by the constant 3 • -22 = -66
Step-2 : Find two factors of -66 whose sum equals the coefficient of the middle term, which is -5 .
-66 + 1 = -65 -33 + 2 = -31 -22 + 3 = -19 -11 + 6 = -5 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -11 and 6
3x2 - 11x + 6x - 22
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (3x-11)
Add up the last 2 terms, pulling out common factors :
2 • (3x-11)
Step-5 : Add up the four terms of step 4 :
(x+2) • (3x-11)
Which is the desired factorization
Thus the answer is 0
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