Question

x-2 is a common factor of polynomial x²_ax+10 x_bx_2 then find the value of ,a,​

Answer 1

Answer:

Answer=7

Explanation:

Let P(x)=x^2-ax+10

and G(x)=x-2

so,

G(x)=0

x-2=0

x=2

p(x)=x^2-ax+10

p(2)=2^2-a×2+10

P(2)=4-2a+10

P(2)=14-2a

0=14-2a

-14= -2a

-14/-2=a

14/2=a

7=a

so,

a=7