Question

X + 2 is a factor of m x cube + 1 X square + X - 6 8 leaves the remainder 4 when divided by x minus 2 find m and n

Answer 1

Step-by-step explanation:

after correction the polynomial

=> mx³+nx²+x-68

since, x+2 is a factor=> putting x= -2

=> m(-2)³+n(-2)²+(-2)-68=0

=> -8m³+4n²= 70.....,..........(1)

putting x= 2

=> m×2³+n×2²+2-68= 4 ....... given

=> 8m³+4n²= 70...................(2)

from eqn (1) and (2) m=0 and

8n²= 140

=> n² = 140/8= 17.5

=> n= √17.5 = 4.183

therefore m=0 and n = 4.183

hope this helps you