Question

x - 2 is a factor of x³ - 8

Answer 1

Hello user

x^3 - 8 = (x - 2)(x^2 + 4 + 2x)

so x-2 is factor of x³ - 8

Answer 2

let p ( x ) = x^3 - 8

and g( x ) = x - 2 = 0

x = 2
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solve for P (2 )
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p ( 2 ) = ( 2 )^3 - 8 = 8 - 8 = 0

p ( 2 ) = 0

therefore , ( x - 2 ) is a factor of given cubic polynomial .