Question

x= -2 is a root of the equation x^2+2x+1=0 (a)True (b)False (c)cant say

Answer 1

$\underline{\huge\bf\red{False}}$

let $p(x) = {x}^{2} + 2x + 1 = 0$
and, we have that x = - 2

This will be the root of p( x ) only when : $\boxed{p( - 2) = 0}$

So, let's check ☑ :—

$\quad \: p( - 2) \\ = {( - 2)}^{2} + 2( - 2) + 1 \\ = \cancel{4} - \cancel{4} + 1 \\ = 1$

Thus, $\underline{ \boxed{ \qquad p( - 2) \: \neq \: 0 \qquad }}$

Hence, [ x = - 2 ] is not a root of p( x ) .
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$\underline{\huge\bf\green{Brainliest \: Answer}}$

Answer 2

Answer:

THE STATEMENT IS FALSE

Step-by-step explanation:

Since (-2)^2 + 2× (-2) + 1 = 4-4+1 = 1 # 0

So

x= -2 doesn't satisfy the equation x^2+2x+1=0

So x= -2 is not a root of the equation x^2+2x+1=0

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