Math, asked by revanth6498, 1 year ago

(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and n​

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Answered by sujal1732
7

Answer:

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(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and n

(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and nAsk for details Follow Report by TbiaSamishta 20.11.2018

(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and nAsk for details Follow Report by TbiaSamishta 20.11.2018Answers

(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and nAsk for details Follow Report by TbiaSamishta 20.11.2018AnswersMe · Beginner

(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and nAsk for details Follow Report by TbiaSamishta 20.11.2018AnswersMe · BeginnerKnow the answer? Add it here!

(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and nAsk for details Follow Report by TbiaSamishta 20.11.2018AnswersMe · BeginnerKnow the answer? Add it here! aqibkincsem Genius

(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and nAsk for details Follow Report by TbiaSamishta 20.11.2018AnswersMe · BeginnerKnow the answer? Add it here! aqibkincsem GeniusMx3+nx2+x-6 has (x+2) as a factor and it leaves a remained of 4 divide by x-2. 3(11+3m+n)=3(1) 11+3m+n=1, 3m+n=-10.

(x+2) is factor of mx^3+nx^2+x-6.it leaves the remainder 4 when divided by (x-2).find m and nAsk for details Follow Report by TbiaSamishta 20.11.2018AnswersMe · BeginnerKnow the answer? Add it here! aqibkincsem GeniusMx3+nx2+x-6 has (x+2) as a factor and it leaves a remained of 4 divide by x-2. 3(11+3m+n)=3(1) 11+3m+n=1, 3m+n=-10.Name it as eq.2, On substracting eq.1 and 2, we get:-m=3, m=-3. Put this value of m in any eq.1 or 2, to get n=-1. So we get n=-1 as the answer by dividing with 4.

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