Question

x=2 is one zero of the polynomial p(x) =4x^2-2x+k-4.find the value of k​

Answer 1

Answer:

answer for the problem is 12

Answer 2

Answer:

$\green{k=-8}$

Step-by-step explanation:

$p(x) = 4x {}^{2} - 2x + k - 4$

To find the value of k we need to insert the zeroes

$4(2) {}^{2} - 2(2) + k - 4 = 0$

$16 - 4 + k - 4$

$8 + k = 0$

$k = - 8$