Question

X^2+kx+3=0 if one root is 1 than other root will be ?

Answer 1

Hey user !!

So here's u r answer !!

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Put x = 1 in the given polynomial

( 1 ) ^2 + K ( 1 ) + 3 = 0

1 + 3 + K = 0

4 + K = 0

K = - 4

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Answer 2

Hey dude!!

Here's your answer

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$f(x) = {x}^{2} + kx + 3 \\ f(1) = {(1)}^{2} + k \times 1 + 3 = 0 \\ 1 + k + 3 = 0 \\ k + 4 = 0 \\ k = - 4$
The other root is -4

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Hope it helps.....!!