Question

x^2 + Kx - 68= 0.find the value of x​

Answer 1

Answer:

$ANSWER</p><p></p><p>Given,</p><p></p><p></p><p>kx(x−2)+6=0</p><p></p><p></p><p>kx2−2kx+6=0</p><p></p><p></p><p>Since the roots are equal,</p><p></p><p></p><p>⇒b2=4ac</p><p></p><p></p><p>(−2k)2=4(k)(6)</p><p></p><p></p><p>4k2=4k(6)</p><p></p><p></p><p>∴k=6</p><p></p><p>$