Question

x^2+kx+k has repeated roots. Find the value of k?​

Answer 1

d=k^2-4k

=k^2-4k

k(k-4)

d =0

hence k belongs R-(0,4)

Answer 2

${x}^{2} + kx + k$

has repeated roots i.e. both the roots are same

delta=0

${k}^{2} - 4k = 0 \\ \\ k(k - 4) = 0 \\ \\ k = 0 \\ \\ k = 4 \\ \\ if \: k = 0 \\ \\ x = 0 \: is \: the \: root\\ \\ if \: k = 4 \\ \\ x = - 2 \: is \: the \: root$

hope it helps.