Math, asked by anuragdhende, 8 hours ago

x^2<2x+8 solve inequalities​

Answers

Answered by Harshgupta123
0

Answer:

x € (-2, 4)

Step-by-step explanation:

Please refer to the given photo.

And mark my answer as BRAINLIEST...

Attachments:
Answered by annamariya9961
2

x^{2} \leq 2x+8\\\\x^{2} -2x=8\\\\x^{2} -2x-8=0\\\\(x-4) (x+2)\\\\(x-4)\\x-4=0 \\x=4\\\\(x+2)\\x+2=0\\x=-2\\\\x=4,-2\\\\x\leq -2\\False\\\\-2\leq x\leq 4\\True\\\\x\geq 4\\Flase\\\\

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