x^2-px+12=(x-3)(x-a), a&p=?
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x^2-px+12=(x-3)(x-a)
x^2-px+12 = x^2-xa-3x +3a
x^2-px+12 = x^2-(a+3)x +3a
by comparison:
-p = -(a+3)
=> p = a+3...............(i)
and
12= 3a
=> a = 4
from (i). p=7
hope it works ☺️❤️
plz mark it as brainliest answer
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