Question

x^2 + px -2 = (x-1)(x+q)​

Answer 1

$(x - 1)(x + q) \\ x(x + q) - 1(x + q) \\ {x}^{2} + xq - x - q \\ {x}^{2} + (q - 1)x - q$

Since,

${x}^{2} + px - 2 = (x - 1)(x + q)$

On comparing

$q = 2$

And

$p = q - 1 \\ p = 2 - 1 \\ p = 1$

Therefore,

Therefore,q = 2 and p = 1

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