Question

X=2-root 3 find the value of (x-1/x)queb

Answer 1

That's your answer.

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Answer 2

Here is your solution

Given :-

x=2-√3

Now

$\frac{1}{x} = \frac{1}{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } \\ \frac{1}{x} = \frac{2 + \sqrt{3} }{2 {}^{2} - ( \sqrt{3}) {}^{2} } \\ \frac{1}{x} = \frac{2 + \sqrt{3} }{4 - 3} \\ \frac{1}{x} = 2 + \sqrt{3}$

$x - \frac{1}{x} = 2 - \sqrt{3} -(2 + \sqrt{3}) \\ x - \frac{1}{x} = -2\sqrt{3}$
Hope it helps you