Question

X=2+root 3
Y= 1/2-root3
Then find the value of 8xy(xsquaare -y square )

Answer 1

Given :-

• x = 2 + √3
• y = 1/2 - √3

To Find :-

• 8xy(x² - y²)

Solution :-

→ x = (2 + √3)

→ y = 1/(2 - √3) => (1/2 - √3) * (2 + √3)/(2 + √3) = (2 + √3)/(4 - 3 = 2 + √3

so,

→ x = y = (2 + √3)

then,

→ 8xy(x² - y²)

→ 8 * x * x * (x² - x²)

→ 8x² * 0

→ 0 (Ans.)

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Let a, b and c be non-zero real numbers satisfying (a³)/(b³ + c³) + (b³)/(c³ + a³) + (c³)/(a³ + b³)

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if a²+ab+b²=25

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