Question

x^2 - ( root2+1)x+ root2 = 0
Solve by completing the square method​

Answer 1

Answer:

x² -(√2 +1)x + √2 = 0

x² - √2 x - x +√2 = 0

x² -x -√2 x +√2 = 0

x(x-1) -√2(x -1) = 0

(x-√2)(x-1) = 0

hence, x = √2 and 1

Answer 2

Hey sis

x=√2 or 1 The derived answer with steps is explained in the image