Math, asked by sakshisinghal211o, 5 months ago

x^2/sinx is a Even and odd function

Answers

Answered by cnchaudhary
0

Step-by-step explanation:

For f(x)=x2+sinx

For f(x)=x2+sinxwe check f(−x) .

For f(x)=x2+sinxwe check f(−x) . If f(−x) simplifies to f(x) , then f is even,

If f(−x) simplifies to −f(x)=−(x2+sinx) , the f is odd.

If f(−x) does not simplify to one of the above, then f is neither even nor odd.Sep 26, 2015

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