Math, asked by sunnykumar7991, 8 months ago

x^2+sinx/xcosx find the derivation of​

Answers

Answered by Anonymous
3

Step-by-step explanation:

Hi

u just need to follow the. u/v rule of differentiation

which is

u= x^2+sinx

v= xcosx

= (u)'v - (v)'u / (v)^2

=( 2x+cosx).xcosx - (x^2+sinx). (cosx-xsinx)

------------------------------------------------

(xcosx)^2

=.( 2x^2cosx+xcos^2x)- (cosx^3-xsinx^3+sinx.cosx-xsin^2x)

--------------------------------------------------------

(xcosx)^2

that was your answer

hope it helps you

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