x^2+sinx/xcosx find the derivation of
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Step-by-step explanation:
Hi
u just need to follow the. u/v rule of differentiation
which is
u= x^2+sinx
v= xcosx
= (u)'v - (v)'u / (v)^2
=( 2x+cosx).xcosx - (x^2+sinx). (cosx-xsinx)
------------------------------------------------
(xcosx)^2
=.( 2x^2cosx+xcos^2x)- (cosx^3-xsinx^3+sinx.cosx-xsin^2x)
--------------------------------------------------------
(xcosx)^2
that was your answer
hope it helps you
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