Question

X=2+
$x = 2 + \sqrt{3} prove \: thatx {}^{2} - 4x + 1 = 0$
3 prove that 3²-42+1=0​

Answer 1

Step-by-step explanation:

we have,

$x = 2 + \sqrt{3}$

$x - 2 = \sqrt{3}$

Squaring both sides, we get,

${x}^{2} - 4x + 4 = 3$

$\implies {x}^{2} - 4x + 1 = 0$