Question

X^2-under root 3x-6
factorise

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I AM CLASS 8

Answer 1

Answer:

The Correct Answer is

$x = \frac{\sqrt{3} + 3 \sqrt{3} }{2} \\ x = \frac{\sqrt{3} - 3 \sqrt{3} }{2}$

Step-by-step explanation:

Given,

$x {}^{2} - \sqrt{3} x - 6 \\ = x = \frac{ - ( - \sqrt{3}) + - \sqrt{( - \sqrt{3}) {}^{2} - 4 \times 1 \times ( - 6) } }{2 \times 1} \\ = x = \frac{ \sqrt{3} + - \sqrt{ \sqrt{3} {}^{2} + 24 } }{2} \\ = x = \frac{ \sqrt{3} + - \sqrt{3} + 24}{2} \\ = x = \frac{ \sqrt{3} + \sqrt{27} }{2}$

Hope this will help you!

Answer 2

Answer:

(x+✓3) (x-2✓3)

Step-by-step explanation:

x^2-✓3x-6

=x^2-2✓3x+✓3x-6

=x(x-2✓3)+✓3(x-2✓3)

=(x+✓3)(x-2✓3)